Question 275526
If the sum of two positive integers is 43 and the difference of their squares is 43, then the smaller integer is


Let one integer be x

The other integer will be 43-x

The difference of squares = 43

x^2-(43-x)^2=43

(x+43-x)(x-43+x)=43
43(2x-43)=43

2x-43=1
2x=44
x=22

The other number will be 43-22 =21

The smaller number is 21