Question 33672
One machine = 2x
Other machine = x
Equation:
 {{{1/2x+1/x=1/8}}} or {{{1/2x+1/x=0.125}}}
(2x+x)=0.125[(2x)(x)]
3x=0.25x^2
0.25x^2-3x=0
times the equation by 4:
x^2-12x=0
Differentate with respect to x
{{{dy/dt=(2x)dx/dt-(12)/dx/dt}}}
-2x=-12
x=6
Mutliply the results by 2:
2(6)=12
Hence, one machine can produce 12 pages and other can produce 2(12)=24 pages.
Paul.