Question 275286
Chuck throws a rock with an initial upward velocity of 12m/sec.  How high is it after 0.7 seconds?
.
y = (1/2)at^2 + vt 
where
'y' is the height
'a' is gravity -9.8 m/sec^2
v is initial velocity
t is time
.
y = (1/2)(-9.8)(0.7)^2 + (12)(0.7) 
y = (-4.9)(.49) + 8.4
y = 6 m