Question 275174
How many liters of a 10% alcohol solution must be mixed with 10L of a 4% solution to get a 6% solution?
I set the problem up as .04(10)+.10x=.06
I ended up with -3.4 , this cannot be. What am I doing wrong?
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You are close, but the equation should be:
.04(10) + .10x = .06(x+10)
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