Question 274610
{{{x/(x-2)}}} - {{{(x-2)/(x+2)}}} 
The common denominator will be(x-2)(x+2), so we have:
{{{(x(x+2) - (x-2)(x-2))/((x+2)(x-2))}}}
:
{{{(x^2 + 2x  - (x^2 - 4x + 4))/((x-2)(x+2))))}}} 
remove the brackets, change the signs
{{{(x^2 + 2x  - x^2 + 4x - 4)/((x-2)(x+2))))}}}
x^2's cancel so you have:
{{{(6x - 4)/((x-2)(x+2))))}}}
Factor
{{{(2(3x - 2))/((x-2)(x+2))))}}}