Question 273945
Let x = "a number". Then "a number is added [to] twice its square, the result is 6" translates into:
{{{x + 2x^2 = 6}}}
Solving this:
{{{x + 2x^2 - 6 = 0}}}
{{{2x^2 + x - 6 = 0}}}
{{{(2x-3)(x+2) = 0}}]
{{{2x-3 = 0}}} or {{{x+2 = 0}}}
{{{x = 3/2}}} or {{{x = -2}}}