Question 274726
2b SQRT^3(16b^2) + SQRT^3(128b^5)
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Do you mean 2b(cube root of 16b^2) + (cube root of 128b^5)
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If so you get:
2b(2*cbrt(2b^2)) + 4b*cbrt(2b^2)
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(4b + 4b)*cbrt(2b^2)
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8b*cbrt(2b^2)
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Cheers,
Stan H.