Question 274703
Since {{{(n+5)!=(n+5)(n+5-1)!=(n+5)(n+4)!}}}, this means that {{{(n+5)!/(n+5)=((n+5)(n+4)!)/(n+5)=(cross((n+5))(n+4)!)/cross((n+5))=(n+4)!}}}



In other words,  {{{(n+5)!/(n+5)=(n+4)!}}}