Question 274662
The basic question will look like this negative 3 is less thank or equal to 3 minus 2x over 3 (fraction form) is less than or equal to 3.

{{{-3<=((3-2x)/3)<=3}}} i hope i got the question written correctly from you.
u solve for x with the 2 seperate equations and remember dividing by a negative chages directions of the inequality signs.
{{{-3<=((3-2x)/3)<=3}}}
{{{-3<=((3-2x)/3)}}} and {{{((3-2x)/3)<=3}}}
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{{{-3<=((3-2x)/3)}}} first equation
{{{-3(3)<=((3-2x)/3)(3)}}}multiply by 3
{{{-9<=((3-2x)/cross(3))cross(3)}}}cross cancel
{{{-9-3<=(3-2x)-3}}}subtract 3
{{{-12/-2<=-2x/-2}}}divide by -2, remember what i said above
{{{6>=x}}}
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{{{((3-2x)/3)<=3}}}second equation
{{{((3-2x)/3)(3)<=3(3)}}}multiply by 3
{{{((3-2x)/cross(3))cross(3)<=9}}}cross cancel
{{{3-2x-3<=9-3}}}subtract 3
{{{-2x/-2<=6/-2}}}divide by -2, remember what i said above
{{{x>=-3}}}
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the inequality will look like:
{{{-3<=x<=6}}} so x= (-3,6)