Question 274543
the equation is y = {{{5/(3x^2-75)}}}


{{{3x^2 - 75}}} is the same as {{{3*(x^2-25)}}} is the same as {{{3*(x-5)*(x+5)}}}


your equation becomes:


y = {{{5/(3*(x-5)*(x+5))}}}


the denominator will be equal to 0 when x = 5 or x = -5.


your equation will be undefined at those values for x.


the graph of your equation looks like this:


{{{graph(600,600,-8,8,-5,5,5/(3x^2-75))}}}