Question 33632
Solve by completing the square:
{{{x^2+8x+13 = 0}}}First subtract 13 from both sides of the equation.
{{{x^2+8x = -13}}} Now complete the square in the x-terms by adding the square of half the x-coefficient {{{(8/2)^2 = 16}}} to both sides.
{{{x^2+8x+16 = 16-13}}} Factor the left side.
{{{(x+4)^2 = 3}}} Take the square root of both sides.
{{{x+4}}} = + or - {{{sqrt(3)}}} Finally, subtract 4 from both sides.

{{{x = -4+-sqrt(3)}}}