Question 274402
The difference of the squares of two consecutive negative integers is 9. Find the integers
{{{-x^2-(-x+1)^2=9}}}
{{{-x^2+(x-1)^2=9}}}
{{{-x^2+(x-1)(x-1)=9}}}
{{{-x^2+(x^2-x-x-1)=9}}}
{{{-x^2+x^2-2x-1=9}}}
{{{-2x-1=9}}}
{{{-2x=10}}}
{{{x=-5}}}
intergers are x,(x+1) whith are -5,-4.
{{{(-5^2)-(-4^2)=9}}}
{{{25-16=9}}}
{{{9=9}}}
correct