Question 274372
You have the right equation. Now let's solve for 'x'.


{{{x(x+2)= (x+2)^2-38}}} Start with the given equation.



{{{x^2+2x= (x+2)^2-38}}} Distribute



{{{x^2+2x= x^2+4x+4-38}}} FOIL



{{{2x= 4x+4-38}}} Subtract {{{x^2}}} from both sides.



{{{2x=4x-34}}} Combine like terms on the right side.



{{{2x-4x=-34}}} Subtract {{{4x}}} from both sides.



{{{-2x=-34}}} Combine like terms on the left side.



{{{x=(-34)/(-2)}}} Divide both sides by {{{-2}}} to isolate {{{x}}}.



{{{x=17}}} Reduce.



----------------------------------------------------------------------


Answer:


So the solution is {{{x=17}}} 



So the two numbers are 17 and 19.