<PRE><B>Question 274307</B>
write the equation y=a(x-h)^2+k with the given. 
with a y-intercept 10, x-intercept 2, and equation of axis x-3=0
----
You have three points: (0,10), (2,0) and vertex(3,y)
---
If vertex is (3,y), h=3.
y = a(x-3)^2+k
-----
Substituting (0,10) and (2,0)
10 = a(-3)^2 + k
0 = a(-1)^2 + k
---
Solve for a and k:
9a + k = 10
a + k = 0
----------------------
8a = 10
a = 5/4
---
k = -5/4
--------------------
y = (5/4)(x-3)^2 - (5/4)
----
{{{graph(400,300,-10,10,-10,10,(5/4)(x-3)^2-(5/4))}}}
----
Cheers,
stan H.</PRE>