Question 274252
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In either problem, use the point-slope form of the equation of a line.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] are the coordinates of a given point and *[tex \Large m] is the slope of the desired line.


In the first problem, you will have to compute the slope from the coordinates of the two given points, thus:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ m\ =\ \frac{y_1\ -\ y_2}{x_1\ -\ x_2} ]


where *[tex \Large \left(x_1,y_1\right)] and *[tex \Large \left(x_2,y_2\right)] are the coordinates of the given points.


In the second problem, you can determine the slope of the desired line because the desired line is presented in slope-intercept form.  The slope is the value of the coefficient on *[tex \Large x].  Furthermore, parallel lines have equal slopes, that is to say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \parallel\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ m_2]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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