Question 274196
 Two planes having the same airspeed depart simultaneously from the airport, flying in opposite directions.
 One plane flies directly into a 35mph wind, and the other flies in the same direction as the wind.
 After a period of time, one plane has traveled 460 miles and the other has traveled 404 miles.
 Let x= the airspeed of each plane (note: this is only possible because the airspeed is the same.)
:
Here is how I would do it.
:
Both planes travel time is the same, write a time equation: time = dist/speed
:
{{{460/((x+35))}}} = {{{404/((x-35))}}} 
Cross multiply
460(x-35) = 404(x+35)
:
460x - 16100 = 404x + 14140
:
460x - 404x = 14140 + 16100
:
56x = 30240
x = {{{30240/56}}}
x = 540 mph plane speed in still air
:
:
Check solution by finding the travel time of each a/c, should be the same:
460/575 = .8 hrs
404/505 = .8 also