Question 273782
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Let *[tex \Large x] represent the first integer, then *[tex \Large x\ +\ 2] represents the next larger one, and *[tex \Large x\ +\ 4] represents the one after that.


The sum is 315, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ x\ +\ 2\ +\ x\ +\ 4\ =\ 3x\ +\ 6\ =\ 315]


Just solve for *[tex \Large x]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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