Question 273700
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In general, *[tex \LARGE x^2\ +\ bx\ +\ c] is a perfect square if and only if *[tex \LARGE c\ =\ \left(\frac{b}{2}\right)^2]


So divide -18 by 2 and square the result.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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