Question 273600
In words:
(liters of alcohol from 12% solution + liters of alcohol from 20% solution)/(total liters of final solution) = 14%
given:
{{{.12*6 = .72}}} = liters of alcohol in 12% solution
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Let {{{x}}} = liters of 20% solution needed
{{{(.72 + .2x)/(6 + x) = .14}}}
{{{.72 + .2x = .14*(6 + x)}}}
{{{.72 + .2x = .84 + .14x}}}
{{{.06x = .84 - .72}}}
{{{.06x = .12}}}
{{{x = 2}}}
2 liters of 20% solution are needed
check answer:
{{{(.72 + .2x)/(6 + x) = .14}}}
{{{(.72 + .2*2)/(6 + 2) = .14}}}
{{{(.72 + .4)/8 = .14}}}
{{{1.12/8 = .14}}}
{{{1.12 = .14*8}}}
{{{1.12 = 1.12}}}
OK