Question 273600
In a chemistry class, 6 liters of a 12% alcohol solution must be mixed with a 20% solution to get a 14% solution. How many liters of the 20% solution are needed?

Let the quantity of 20% solution be x liters

12%------------------20%-------------------14% mix

6-------------------- x--------------------x+6    (quantity)

Form an equation with actual parts mixed

0.12*6 + 0.2 x = 0.14(x+6)

0.72+0.2x = 0.14x+0.84

0.2x-0.14x=0.84-0.72

0.06x=0.12

x=2 liters  which is the quantity of 20% alcohol required