Question 273482
This problem is just like mixture problems & is solved the same way
In words:
(number of A.A. students in Wilson H.) + (number of A.A. students in Jefferson H.) / (total number of students in the combined school) = 44%
Let {{{n}}} = number of students in Jefferson H.
given:
{{{400}}} students in Wilson H.
{{{.2*400 = 80}}} A.A. students in Wilson H.
{{{.6n}}} = A.A. students in Jefferson H.
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{{{(80 + .6n)/(400 + n) = .44}}}
{{{80 + .6n = .44*(400 + n)}}}
{{{80 + .6n = 176 + .44n}}}
{{{.16n = 96}}}
{{{n = 600}}}
There are {{{600}}} students at Jefferson H.
check answer:
{{{(80 + .6n)/(400 + n) = .44}}}
{{{(80 + .6*600)/(400 + 600) = .44}}}
{{{(80 + 360)/1000 = .44}}}
{{{440/1000 = .44}}}
{{{.44 = .44}}}
OK