Question 273450
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Let *[tex \Large x] represent the number of years between now and the time that Dad is twice as old as Jack, then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 40\ +\ x]


is the age Dad will be and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 14\ +\ x]


is the age Jack will be and these two ages are related thus:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2(14\ +\ x)\ =\ 40\ +\ x ]


Solve for *[tex \Large x] and then add that amount to each of their ages.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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