Question 33577
<pre><font size = 5><b>
ln(1/x) + lnx = 0

          lnx = -ln(1/x)

Replace 1/x by x<sup>-1</sup>

          lnx = -ln(x<sup>-1</sup>)

Use rule lnB<sup>A</sup> = AlnB

          lnx = -(-1)lnx

          lnx = lnx

Thus this is an identity for all values of x
for which lnx is defined.  lnx is defined for
all positive x, so the solution set is

       {x|x > 0} or (0, <font face = "symbol">¥</font>)

Edwin
AnlytcPhil@aol.com</pre>