Question 273377
<font face="Times New Roman" size="+2">


If A can do a job in <i>x</i> time periods, then A can do *[tex \Large \frac{1}{x}] of the job in 1 time period.  Likewise, if B can do the same job in <i>y</i> time periods, then B can do *[tex \Large \frac{1}{y}] of the job in 1 time period.


So, working together, they can do


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \frac{1}{x}\ +\ \frac{1}{y}\ =\ \frac{x\,+\,y}{xy}]


of the job in 1 time period.


Therefore, they can do the whole job in:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \frac{1}{\frac{x\,+\,y}{xy}}\ =\ \frac{xy}{x\,+\,y}]


time periods.



John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
</font>