Question 273335
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I think you want a line through (-2, 1) parallel to *[tex \Large y = -3x\ +\ 1]


The slope of a line is the coefficient on *[tex \Large x] when the equation is in slope-intercept form.  Parallel lines have equal slopes.


So use the point-slope form of the equation of a line to derive the desired equation:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1) ]



where *[tex \Large \left(x_1,y_1\right)] are the coordinates of the given point and *[tex \Large m] is the slope of the given line.


So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ (1)\ =\ -3\left(x\ -\ (-2)\right)]


Simplification is left as an exercise for the student.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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