Question 273284
You have the first solution of {{{x=1}}}, you just need to solve {{{x^2+10x+24=0}}}



So let's solve {{{x^2+10x+24=0}}} by use of the quadratic formula.



*[invoke quadratic_formula 1, 10, 24, "x"]



So the next two solutions are {{{x=-4}}} and {{{x=-6}}}



This means that the three solutions are {{{x=1}}}, {{{x=-4}}} and {{{x=-6}}}



I'll let you check the solutions.