Question 273268
This is what I came up with. Is this correct?
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Your factoring is correct.
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[(y+2)(3y+7)]/[(y+2)(y+1)] * [(y-2)(2y+1)]/[(3y+7)(y+5)]
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Cancel the y+2 factor:
Cancel the 3y+7 factor:
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(1/(y+1)*[(y-2)(2y+1)/(y+5)] 
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equals to (y-2)(2y+1) divided by (y+1)(y+5)
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You are correct.
Cheers,
Stan H.