Question 33543
You can use the distance formula:
{{{d = rt}}} where: d = distance travelled, r = rate of travel (speed), and t = time of travel.
For the train:
{{{d1 = r1(t1)}}}
1) {{{d1 = 40(t1)}}}

For the bus:
{{{d2 = r2(t2)}}}
2) {{{d2 = 50(t2)}}}

The distance is the same in each case, so d1 = d2, therefore, we can set:
{{{40(t1) = 50(t2)}}}
But the train travels one hour longer than the bus, so t1 = t2+1
Making this substitution, we get:
{{{40(t2+1) = 50(t2)}}} Simplify and solve for t2.
{{{40(t2)+40 = 50(t2)}}} Subtract 40(t20 from both sides of the equation.
{{{40 = 10(t2)}}} Divide both sides by 10.
{{{4 = t2}}} Now substitute this into equation 2) and solve for d2:
{{{d2 = 50(4)}}}
{{{d2 = 200}}}miles.

The town is 200 miles from the starting point.