Question 30958
Please help me! I have to find the remaing roots (zeros) but I'm confused. The problem is f(x)=x^3+2x^2-3x+20. One root is there and it is -4.
OK ..GO AHEAD..YOU SHOULD DIVIDE WITH -4 ..NOT +4....
 I have to find two more roots (zeros). I tried to work it out using synthetic division:
-4|......... 1.......... , 2......... , -3.......... , 20
............0.............-4.............8............-20
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.............1............-2.............5.............0
ANSWER IS 
X^2-2X+5=THIS HAS IMAGINARY ROOTS.AS DISCRIMINANT IS NEGATIVE...USE QUADRATIC FORMULA...
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (2 +- sqrt( (-2)^2-4*1*5 ))/(2*1) }}}
{{{x = (2 +- sqrt( -16 ))/(2) }}}
{{{x = (1 +- (2*i)) }}}