Question 272913
x2+5x-36=0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
x=(-5+-sqrt[5^2-4*1*-36])/2*1
x=(-5+-sqrt25+144)/2
x=(-5+-sqrt169)/2
x=(-5+-13)/2
x=(-5+13)/2
x=8/2
x=4 ans.
x=(-5-13)/2
x=-18/2
x=-9 ans.