Question 272184
[(n + 6) (n + 5) (n + 4) (n + 3)...] / [(n + 4) (n + 3)...] = 12


(n + 6) (n + 5) = 12


n^2 + 11n + 30 = 12


n^2 + 11n + 18 = 0


(n + 9) (n + 2) = 0


n = -9 ___ AND ___ n = -2


negative factorials are not defined, so n = -2