Question 272078
y= -1/2x^2 + 2x + 10 
I have the vertex (2, 12) and the y intercept (0,10) but I keep getting stuck with....
x= -b +/- the square root of b^2 - 4ac over 2a. 
I have it down to x= -2+/- the square root of 24 over -1 from there I am stuck

If you are supposed to solve the above for x we need to get the equation in the form:

ax^2 + bx + c = 0

-1/2x^2 + 2x + 10 = 0

In this case we have a = -1/2, b = 2 and c = 10. Using the quadratic formula then gives you:

-2 +- [sqrt(2^2 - 4*-1/2*10)]/(2*-1/2) =

-2 +- sqrt(4 + 20)/-1 =

-2 +- sqrt(24)/-1

The two solutions then are:

-2 - sqrt(24) and
-2 + sqrt(24)

sqrt(24) = sqrt(4*6) = sqrt(4)*sqrt(6) = 2*sqrt(6) so
we can rewrite the solutions as:

-2 - 2*sqrt(6)
-2 + 2*sqrt(6)