Question 271990
If it's
6^(x-3) = 2^x, then
(x-3)*log(6) = x*log(2)
x*log(6) - 3log(6) = x*log(2)
x(log(6) - log(2)) = 3log(6)
x*log(3) = 3log(6)
x = 3log(6)/log(3)
x =~4.89279