Question 271968
I have to evaluate this function: 
g(t) = -3t^2-t; find g(t/3). 
What I have so far is -3(t/3)^2 - t/3. 
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That's a good start
= -3*(t^2/9) - t/3
= -t^2/3 - t/3
It can be rearranged into different versions
= (-1/3)*(t^2 + t)
= (-t/3)*(t+1)