Question 271920
Quadratic equations have two solutions. And the equation
{{{(x-r[1])(x-r[2]) = 0}}}
is a general form for quadratic equations where the solutions ({{{r[1]}}} and {{{r[2]}}}) can be seen.<br>
Sometimes the solution is "of multiplicity two". This means that there is just one number that counts twice as a solution. In other "words", {{{r[1] = r[2]}}}. Since your problem claims to have just one solution, 1, it must be a solution of multiplicity two. And the equation would be:
{{{(x-1)(x-1)=0}}}
which simplifies to:
{{{x^2 -2x +1 = 0}}}