Question 271934
Diagonal of a rectangle is 15 m. Longer side of rectangle is 12 m. What is perimeter of the rectangle?

The diagonal and the two adjacent sides form a right triangle

Applying the pytahagoras theorem

Diagonal^2 = Length^2 + width^2

15^2= 12^2 +w^2

15^2-12^2 = width^2

225-144 = width^2

81=width^2

9= width

9*2 + 12*2 = perimeter
18+24 = 42 meters