Question 33514
Let #of dimes be "x".
Then # of nickels is "2x"
And # of quarters is "23-x-2x"= "23-3x"
Value of dimes is 10x cents
Value of nickels is 5(2x)=10x cents
Value of quarters is 25(23-3x)= 525-75x cents
EQUATION:
 value + value + value = 245 cents
  10x + 10x + 525-75x = 245
-55x=-330
x=6     (number of dimes
2x = 12 (number of nickels)
23-3x=23-18= 5 (number of quarters)

Cheers,
Stan H.