Question 271818
Are there two consecutive odd numbers such that the difference in their squares is 80?
You may edit the question. Maybe convert formulae to the same formula notation {{{x^2-1}}} as in your solutions.
Are there two consecutive odd numbers such that the difference in their squares is 80?

Let x be the smaller integer. Then the next consecutive odd integer is x+2.

We need to solve:

(x+2)^2 - x^2 = 80

Expanding we have:

x^2 + 4x + 4 - x^2 = 80

4x = 76
x = 19
x+2 = 21