Question 271640
A two-digit number is five times the sum of its digits. The digits from left to right name consecutive integers. Find the number.
0 solutions

Let x be the tens digit. Then the ones digit is the next consecutive integer or x+1.

The number then is 10*x + 1*(x+1).

So we have:

10*x + 1*(x+1) = 5*((x + (x + 1))
10x + x + 1 = 5*(2x + 1)
11x + 1 = 10x + 5

Solve the above for x and then calculate x+1.