Question 271644
Cyclist A started his journey on cycle at 7:30 a.m. at a speed of 8 km/h. After 30 minutes, cyclist B started from the same place but with a speed of 10 km/h. At what time did B overtake A?

A- 8 km/hr

B 10 km/hr

distance traveled by A in 1/2 hour = 4 kms.

x/10 = x-4  / 8

10*(x-4)= 8x

10x-40=8x
10x-8x= 40
2x=40
x=20

They meet after a distance of 20 km.

time taken = distance / speed  

20 /10 = 2 hours

B overtakes A at 9.30 am.