Question 271332
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1.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{240}{r+9}\ =\ \frac{160}{r-9}]


Solve for *[tex \Large r]


2.

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{200}{x}\ =\ \frac{40}{144}]


Solve for *[tex \Large x]


3.


If A can do a job in *[tex \Large x] time periods and B can do a job in *[tex \Large y] time periods, then A can do *[tex \Large \frac{1}{x}] of the job in 1 time period and B can do *[tex \Large \frac{1}{y}] of the job in 1 time period.  Then, working together they can do:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{1}{x}\ +\ \frac{1}{y}\ =\ \frac{x\,+\,y}{xy}]


of the job in one time period.  Therefore they can do the whole job in:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{xy}{x\,+\,y}]


time periods.


Next time, one question per post please.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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