Question 271328
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 15x\ -\ 5y\ =\ 45]


Substitute 0 for *[tex \Large x] and then solve what is left for *[tex \Large y], giving you some value for *[tex \Large y] such as *[tex \Large y\ =\ b].  (Determining the value of *[tex \Large b] is left as an exercise for the student).  That gives you the coordinates of one ordered pair, *[tex \Large \left(0,b\right)], which happens to lie somewhere on the *[tex \Large y]-axis -- hence the name *[tex \Large y]-intercept.


Now repeat the same process substituting 0 for *[tex \Large y] and creating a second ordered pair, interestingly enough called the *[tex \Large x]-intercept, of the form *[tex \Large \left(a,0\right)].  Again, the value of *[tex \Large a] is up to you.


Plot both points.  Draw a line extending all the way across your graph through the two points.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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