Question 270643
For any given graph of a quadratic such as {{{(x^2)+2x+4}}} the 'solutions' are typically x values that make that graph zero. Thus you are looking for the x values when y = 0.

In the graph below your 'solutions' are x=2 and x=-1 since that is where the y values are 0

{{{graph( 300, 200, -5, 5, -5, 5, (-x^2)+x+2)}}}