Question 271060
Remember any number raised to the power of 0 = 1
:
a) [16^(1/2) +(2/3)^0]^-2

[16^(1/2) + 1]^-2
The exponent of 1/2 is the square root of the number
(4 + 1)^-2
5^-2
The reciprocal gets rid of the neg
{{{1/5^2}}} = {{{1/25}}} 
:
:
b)(27/8)^(1/3) + 4^-1
Take the cube root of both numerator and denominator
{{{3/2}}} + {{{1/4}}} = {{{6/4}}} + {{{1/4}}} = {{{7/4}}}
:
:
c)(7^0 - 4^-1)^-3
(1 - {{{1/4}}})^-3 = ({{{3/4}}})^-3 = ({{{4/3}}})^3
cube both the numerator and denominator
{{{64/27}}}