<PRE><B>Question 271115</B>
Please help me solve this equation: {{ b+2/(b+3)+1 = -7/ b-5 }}

(b+2/ b+3 ) + 1 = -7/ (b-5)

b+2 +b+3 / ( b+3) = -7 / (b-5)

2b+5/(b+3) =-7/(b-5)

(2b+5)(b-5) = -7(b+3)

2b^2-10b+5b-25=-7b-21

2b^2 -10b+5b+7b= 25-21

2b^2+2b-4=0

Divide by 2

b^2+b-2 =0

b^2+2b-b-2=0

b(b+2)-1(b+2)=0

(b-1)(b+2)= 0

b= 1 or -2

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