Question 271046
Evaluate:
{{{Log[9](1/81) = x}}} Rewrite in exponential form:
{{{9^x = 1/81}}} Substitute {{{1/81 = 1/9^2}}} = {{{9^(-2)}}}
{{{9^x = 9^(-2)}}} The bases are equal so the exponents are equal.
{{{highlight(x = -2)}}}