Question 270985
we start with
{{{8^(x+8)=32^x}}}
step 1 - rewrite as
(ii) {{{8^x*8^8 = 32^x}}}
Now 32^x = 8^x*4^x.
step 2 - divide by 8^x to get
(iii) {{{8^8 = 8^x*4^x/8^x}}}
step 3  - cancel the 8^x to get
(iv) {{{8^8 = 4^x}}}
step 4 - rewrite both as base 2 to a power as
(vii) {{{(2^3)^8 = (2^2)^x}}}
step 5 - use rules of exponents to get
(viii) {{{2^24 = 2^2x}}}
step 6 - eliminate the base 2's to get
(ix) {{{24 = 2x}}}
step 7 - divide by 2 to get
(x) {{{x = 12}}}