Question 271019
how do you solve [2x^3y^-3z^5][4x^-3y^-2z^-1]
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= 2x^3y^-3[4x^-3y^-2z^-1] - 3z^5[4x^-3y^-2z^-1]
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= 8x^0*y^-5*z^-1 - 12x^-3*y^-2*z^4
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= 8y^-5*z^-1 - 12x^-3*y^-2*z^4
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= [8/y^5*z] - [12z^4/x^3*y^2]
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Cheers,
Stan H.