Question 270845
When you read the problem you see that the dimensions are given in terms of the width. So let A = the width.
A(width) = X
B(height) = X-2
C(length) = 2X

A)The equation for the volume is A*B*C or {{{X*(X-2)*(2X)}}}
B){{{X*(X-2)*(2X) = 150}}}
C){{{(X*(X-2)*(2X)) - 150 = 0}}}




{{{graph(400, 300, -20, 20, -20, 20, x*(x-2)*(2*x)-150)}}}

X = 5,
So with the width being 5ft, plug 5 into the equations for the height and length