Question 270804
Hello, 
We can set up two equations and solve the problem. 
Let x be Crocus and y be daffodil. So:
x+y=40
.45x+.65y=20.40
Multiply the first equation by -.45 so to eliminate x. So we get:
-.45x-.45y=-18 Now add this to the second equation:
+.45x+.65y=20.40 
And we get:
.20y=2.40 Divide each side by .25 to get:
y=12 Now we can find x by plugging 12 for y in the first equation:
x+12=40 Subtract 12 from both sides to get:
x=28
So now we know there are 12 daffodil and 28 crocus. 
RJ
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